The predicted rain has arrived at Manchester in spades, but England are still in a very strong position thanks to their efforts yesterday.
THE MATCH AS IT STANDS
Having secured a first innings advantage of 172 England batted well second time around. Sibley made a half century, Joe Root scored at a very rapid rate throughout his unbeaten half century and Burns managed 90, his dismissal triggering a declaration which left the West Indies 399 to make to win the match and England six overs to bowl yesterday evening. Broad who had terminated the first West Indies innings with extreme prejudice earlier in the day produced another magnificent spell of bowling, bagging the wickets of John Campbell (84 runs in the series for the opener, a performance reminiscent of that of another left handed attacking opener, David Warner in last year’s Ashes) and nightwatchman Kemar Roach to take his tally of test wickets to 499. The West Indies ended that mini-session at 10-2 off six overs, needing a further 389 to win. There has been no play thus far today due to the rain, but it is no longer raining in Manchester (it is rodding it down here in King’s Lynn) and the umpires have thrown down a challenge to Jupiter Pluvius by declaring that they will inspect at 3PM if there is no further rain. Of course England declared yesterday evening precisely because we were expecting little if any play today, and the forecast for tomorrow is good (and Old Trafford is, as it needs to be, a quick draining ground). Unless one of the remaining West Indies batters can somehow channel the Lord’s 1984 version of Gordon Greenidge the only question is whether we will see enough cricket today and tomorrow for England to get those final eight wickets.
SOLUTION TO YESTERDAY’S TEASER
I offered the following choices:
Brilliant had offered as it’s three possible answers less than 1, between 1 and 2, and 2. Anyone who has read about fractal geometry knows that the fractal dimension of a line is always between 1 and 2, so this selection of answers constituted a give away, reducing a three-dagger problem to a one-dagger joke.
In this case the calculations give an answer of approximately 1.33, so the correct choice from the selections I offered is b) 1.25-1.50.
Here is a published solution by Mateo Doucet De Leon:
PICTURES AND AN UPDATE
Today’s pictures are of coins. A return to employment with James and Sons Auctioneers is on the horizon, although current circumstances make it impossible to predict when this will happen, but I have agreed to do some imaging from home in the meantime, and the first consignment of stock to be imaged arrived yesterday. The auction can be viewed here. Below are some of the lots I have already imaged…