Action Underway In All Championship Fixtures

A look at the county championship, solution to yesterday’s mathematical teaser and plenty of photographs.

The game between Somerset and Surrey has just got underway after the first four sessions fell victim to the weather which means that all matches now have some play. This post scouts round the grounds to see what is going on.


Essex v Derbyshire: Essex batting first are 138-1 after 34.5 overs (no play yesterday). Sir Alastair Cook is unbeaten on 58, while big Billy Stanlake has the one wicket to fall but has been expensive, going at almost five an over. Nick Browne, the man out, scored 59, and Westley is at the crease with Cook.

Durham v Worcestershire: Durham scored 246 batting first and Worcestershire are 98-4 in response. Ben Raine has 2-11 and Chris Rushworth 2-38 for Durham and Tom Fell 40 not out for Worcs. Lees made 99 for Durham, with Brydon Carse second top scorer with 38 not out. Tongue claimed 5-39 for Worcs.

Sussex v Kent: Sussex are 177-4, already 32 ahead of Kent with six first innings wickets still standing. Tom Clark is 36 not out and Ben Brown 21 not out. Stiaan Van Zyl made 52. Darren Stevens who made his FC debut five years before Clark was even born, has 2-45 and Nathan Gilchrist 2-46.

Glamorgan v Yorkshire: Glamorgan are 96-7, play having started a day late due to the weather. Harry Brook, mainly a batter, has 3-15 with his medium pace, Steven Patterson 2-15 and Ben Coad and Jordan Thompson each have a wicket. David Lloyd made 31 and Billy Root 23. At the moment Michael Neser and Andrew Salter are batting for Glamorgan. Glamorgan’s other Aussie, Labuschagne, managed just 10. Glamorgan were 69-2 at one point before slumping to 82-7.

Middlesex v Hampshire: Middlesex are 163-9. This match saw one session of play yesterday and most of today’s scheduled play although there was an interruption for bad light. Gubbins made 51 for Middlesex, his fourth 50+ score of the season, while Blake Cullen scored 27. Kyle Abbott has 5-44 and Mohammad Abbas 3-42.

Somerset v Surrey: Surrey are 14-0 in the fifth over. There is no brother v brother element in this game as Craig Overton is not playing for Somerset. Leach is also rested, which means that Roelof van der Merwe is playing. Burns has 6 not out, Stoneman 7 not out. Gregory and Davey are bowling for Somerset, with De Lange first chance and Tom Abell possibly bowling ahead of van der Merwe in the circumstances. Craig Overton has been rested at the request of the ECB, which suggests that an England recall beckons for the Devonian giant.


The XI I picked is shown below (go here to try it yourself), and then I provide some supplementary notes:

You are given a list of options for each position, and some of the choices they provide are obviously flawed. My own selection is uncontroversial as regards the top seven – Woakes has to be an automatic pick in England, and absent Stokes who is recovering from injury, he is the only one fitted to play the role of genuine all rounder. I opted for Craig Overton at eight, because Oliver Edward Robinson was not available to be selected there, though Archer was. I could have picked Archer at eight and Robinson at nine and then explained that I would actually reverse their batting positions but decided to go for Overton instead and explain the situation in more detail. Overton is in magnificent form and I am not too worried about this personnel change. Archer bowled beautifully for Sussex yesterday and is clearly fit and firing, though Olly Stone could also be awarded that slot and the Durham duo of Mark Wood and Brydon Carse are also both possibles. Leach has to play if fit (if not Parkinson comes in), and I have gone for Anderson out of the veterans.


Yesterday I presented the following:

The answer to the above is 18. I offer two of the published explanations, first a masterpiece of brevity from David Vreken:

David Vreken
May 11, 2021

By casting out the nines, (E+A+R)+(E+R+A)−(A+R+E)=A+R+E(E + A + R) + (E + R + A) – (A + R + E) = A + R + E(E+A+R)+(E+R+A)−(A+R+E)=A+R+E must be divisible by 999.

Out of the given options, only 181818 is divisible by 999, so A+R+E=18A + R + E = \boxed{18}A+R+E=18​.

For those who prefer a more thorough approach here is a complete explanation from Inesh Chattopadhyay:


Time for my usual sign off:

As I prepare to put this up, Surrey have moved on to 50-1, Stoneman back in the hutch, Burns in to the 20s, continuing his strong start to the season, and Amla just starting.

Author: Thomas

I am a founder member and currently secretary of the West Norfolk Autism Group and am autistic myself. I am a very keen photographer and almost every blog post I produce will feature some of my own photographs. I am an avidly keen cricket fan and often post about that sport.

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