A Demanding Week and a New Computer

My first post created using my new computer. It covers my work for James and Sons this week and includes solutions to the puzzle contained in my previous blog post.

INTRODUCTION

Welcome to this post, the first to be composed using my brand new Acer Chromebook 15, of which more later. As well as covering the events of Tuesday, Wednesday and Thursday, with a few pictures, and of course explaining the computer situation I will be providing an answer the puzzle that I included in my last post.

THE COMPUTER SITUATION

My old computer (and by computer standards it was a veritable Methusalah) had been struggling for some while when it finally decided to give up the ghost completely. My mother by way of an early Christmas present transferred the funds necessary to buy a replacement to my account, and I made the purchase today. All I am now waiting for is the arrival of the hard drive caddy that I ordered online which will enable me to connect the hard drive that I extracted from my old computer to this one and all will again be as it should be.

A HEAVY WORKLOAD AND HEAVY LIFTING

James and Sons had its last auction of this year on Wednesday (our next auction is taking place on January 18, 19 and 20 at our shop in Fakenham), and on either side of that I was getting as many images ready for January as I could. The auction we have just had took place in Norwich, and a shortage of people available to help combined with the fact that one of my colleagues was experiencing knee trouble meant that most of the heavy lifting had to be done by yours truly.

DAY 1: TUESDAY

Most of the work of loading the van had been accomplished on the Friday, but some still remained to be done. Additionally there were last minute queries to be resolved, work to be done for our next auction and a few other things. I made enough of a fuss about the extra expense of catching the very early bus to Norwich (a First Eastern Counties X1, which leaves at 5:30AM and on which a return costs £11 as opposed to the £5.50 it would have cost me if I could have caught the Stagecoach X29 which leaves at 6:28AM) that I was authorised to extract the bus fare from the till.

DAY 2: WEDNESDAY

I managed to catch the 5:30AM bus, and was the first James and Sons employee at the venue. Once the van arrived it was time to unload everything and get the place set up for the auction. After a few hitches, including requiring an emergency replacement for the computer which we had been using to run the auctioneer’s view screen we got underway on time at 10AM, and the sale proceeded fairly smoothly. The coins fared especially well, and much to my relief some of the larger boxes of stamps sold in the room, meaning that they did not have to go back on the van. The militaria also did well. 

Once the van was loaded I was able to take my leave, and being in Norwich took the opportunity to visit Norwich Millennium Library before getting the bus home. In the end I arrived back at my flat a little under 14 hours after I had left it in the morning.

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These old coins fared especially well, two of them (213 and 215 fro memory) going for £170 each after protracted online bidding battles.

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DAY 3: THURSDAY

After unloading the sold goods from the van it was back to work on the January auction. The catalogue cover was ready by the end of the day, and the images were about 70% done, a near miracle in the circumstances. Here are some of the new images from yesterday…

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These postcards were needed for the catalogue cover, so with time pressing I scanned them at 150 DPI – and they looked superb on the printed page.

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THE PUZZLE EXPLAINED

I asked you to take any three digit number, multiply by 7, then multiply the new answer by 11 and finally multiply that answer by 13. I then asked how your final answer compared to your original number. That final answer consists of two copies of your original number. The reason for this is that 7 x 11 x 13 = 1,001 – and that post beinbg my 1,001st on aspiblog was why I set that puzzle in it. As a bonus I asked what multipliers you would need to produce a similar effect with four digit numbers, and the answer to that is 73 and 137, because 73 x 137 = 10,001.